x^2-40x-6000=0

Solution for x^2-40x-6000=0 equation:

x^2-40x-6000=0

a = 1; b = -40; c = -6000;
Δ = b2-4ac
Δ = -402-4·1·(-6000)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-160}{2*1}=\frac{-120}{2}
=-60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+160}{2*1}=\frac{200}{2}
=100
$